Question

. Factorise : 3y2 + 14y + 8​

Answer 1

Answer:

correct answer given.hope it helps

Answer 2

${\underline{\underline{\star{\sf{Question:}}}}}$

Factorise:

$\bf{3y^2+14y+8}$

${\underline{\underline{\star{\sf{According\:to\:the\:Question:}}}}}$

We need to factorise the given quadratic equation. This method is simple, just we are going to split the middle term. Let's solve it step by step.

${\underline{\underline{\star{\sf{Solution:}}}}}$

$\implies\bf{3y^2+14y+8}$

Now, we are going to split the middle term, 14y

14y can be written as 12y + 2y so that,

• If we add, (12y + 2y) you will get 14y, which is nothing but the middle term.

• If we multiply, (12y × 2y) you will get 24y²

$\implies\bf{3y^2+14y+8}$

$\implies\bf{3y^2+12y+2y+8}$

Now, let us take 3y and 2 as common:

• 3y²+14y = 3y(y+4)

• 2y+8 = 2(y+4)

$\implies\bf{3y(y+4)+2(y+4)}$

$\implies{\underline{\boxed{\pink{\pmb{\sf{(y+2)(y+4)}}}}}}$

Hence, factorised.