Math, asked by KingMallick, 1 year ago

factorise 3y²+14y+8​

Answers

Answered by Anonymous
20
\huge\bf\green{\mid{\overline{\underline{Solution}}}\mid}

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3 {y}^{2} + 14y + 8 \\ = > 3 {y}^{2} + 12y + 2y + 8 \\ = > 3y(y + 4) + 2(y + 4) \\ = > (3y + 2)(y + 4) \\ = > y = ( \frac{ - 2}{3} )( - 4)

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rahul8198: Hlw
Answered by biswasdipranil
7

Answer:

(y+4)(3y+2)

Step-by-step explanation:

3y²+14y+8

3y(y+4)+2(y+4)

(y+4)(3y+4)

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