Question

factorise : 4(a+b)-6(a+b)^2​

Answer 1

Answer:

2(a+b)[2-3(a+b)]

Step-by-step explanation:

let (a+b) be x

therefore,

4x-6x^2

=2x(2-3x)

substituting the value of x

2(a+b)[2-3(a+b)]

Answer 2

Step-by-step explanation:

4(a+b)-6(a+b)^2

= 2 (a+b) [ 2 - 3 (a+ b) ]

= 2 (a+b) [ 2 - 3a - 3b ]

= [ 2a + 2b ] [ 2- 3a - 3b ]

= ( 4a - 6a^2 - 6ab + 4b - 6ab -6b^2)

= 4a +4b -6a^2 -12ab -6b^2

........