Question

factorise :4(p+q)(3a-b) +6(p+q)(2b-3a)

Answer 1

4(p+q)(3a-b)+6(p+q)(2b-3a)
=  2(p+q)[2(3a-b) + 3(2b-3a)]
        =  2(p+q)[6a - 2b + 6b - 9a]
                        =  2(p+q)[4b - 3a]

Answer 2

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