Question

Factorise 4(x-2y)² + 8(x-2y) ​

Answer 1

Answer:

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Step-by-step explanation:

15(x−2y)

2

−8(x−2y)−16

let x-2y=p then,

15(x−2y)

2

−8(x−2y)−16=15p

2

−8p−16

=15p

2

+12p−20p−16

=3p(5p+4)−4(5p+4)

=(5p+4)(3p−4)

Substituting p=x-2y we get

=[5(x−2y)+4][3(x−2y)−4]

=(5x−10y+4)(3x−6y−4)

Answer 2

Step-by-step explanation:

=4*(x-2y)²+8(x-2y)

=4x²-16y²+8x-16y

=(4x²-16y²)+8x-16y

=(4x-16y)²+8x-16y

=((4x²)+(16y)²-2(4x)(16y))+8x-16y

=(16x²+256y²-128xy)+8x-16y

=8x(16x²+256y²-128xy)-16y(16x²+256y²-128xy)

=128x³+2048xy²-1024x²y-256x²y-4096y³-2048xy²

=128x³-1280x²y-4096y³