factorise-4(x+y)=^2-3(x+y)
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See this.
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Given,
To factorise
4(x + y) - 6(x + y)²
Taking out common factor as 2(x + y)
we have,
2(x + y)[ 2 - 3(x + y)
2(x + y)( 2 - 3x - 3y)
Or
(2x + 2y)(2 - 3x - 3y)
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