Factorise:4(x2+1)2 +13 (x2+1)-12
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Answered by
117
4(x²+1)²+13(x²+1)-12
=4(x⁴+2x²+1)+13x²+13-12
=4x⁴+8x²+4+13x²+1
=4x⁴+21x²+5
=4x⁴+20x²+x²+5
=4x²(x²+5)+1(x²+5)
=(x²+5)(4x²+1)
=4(x⁴+2x²+1)+13x²+13-12
=4x⁴+8x²+4+13x²+1
=4x⁴+21x²+5
=4x⁴+20x²+x²+5
=4x²(x²+5)+1(x²+5)
=(x²+5)(4x²+1)
Answered by
18
4(x2+1)2 +13 (x2+1)-12
=4(x^4+2x^2+1)+13x^2+13-12
=4x^4+8x^2+4+13x^2+1
=4x^4+21x^2+5
=4x^4+20x^2+x^2+5
=4x^2(x^2+5)+1(x^2+5)
=(x^2+5)(4x^2+1)
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