write the orbitals in which 18 elements present in 5th period
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When n=5,l=0,1,2,3 and 4. The order in which the enery of the available orbitals 4d,5s and 5p increases in 5s<4d<5p. The total number of orbitals available is 9. The maximum number of electrons that can be accommodated is 18, and therefore 18 elements are there in the 5th period.
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When we complete filling of 4th period by elements in the order of their atomic number, the orbitals 3s² 3p⁶ are full. So we start the 5th period with 4s orbital.
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