Question

factorise 4a^2+12a+9​

Answer 1

$4 {a}^{2} + 12a + 9$

${\implies}4 {a}^{2} + 12a + 9 \\{\implies} 4 {a}^{2} + 6a + 6a + 9 \\{\implies} 2a(2a + 3) + 3(2a + 3) \\{\implies} (2a + 3) (2a + 3) \\{\implies} (2a + 3) {}^{2}$

Answer 2

Answer:

( 2a+3 )(2a+3)

Step-by-step explanation:

4a^2 + 12a + 9 can be factorised by middle term splitting method

for this we have to make sure that product of 4*9 = product of numbers formed by spliting 12

and sum of same numbers = 12

now our equation looks like this

4a^2 + 6a + 6a + 9 ( 4*9 = 36 & 6*6= 36 )

( 6+6 = 12)

2a ( 2a + 3 ) + 3 ( 2a + 3 ) ( by taking Commons)

( 2a + 3) ( 2a + 3)