Question

factorise: 4a^2-3a+4ab-3b​

Answer 1

Step-by-step explanation:

4a^2-3a+4ab-3b

=4a^2+4ab-3a-3b

=4a(a+b)-3(a+b)

=(a+b)(4a-3)

Answer 2

Step-by-step explanation:

$4a {}^{2} - 3a + 4ab - 3b \\ 4a {}^{2} + 4ab - 3a - 3b \\ 4a(a + b) - 3(a + b) \\ (a + b)(4a - 3)$