factorise 4a^2 - 4a +1- b^4
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Given 4a² - 4a + 1 - b⁴
= ( 4a² - 4a + 1 ) - b⁴
= [ ( 2a )² - 2×2a×1 + 1² ] - ( b² )²
= ( 2a - 1 )² - ( b² )²
= ( 2a - 1 + b² )( 2a - 1 - b² )
•••••
= ( 4a² - 4a + 1 ) - b⁴
= [ ( 2a )² - 2×2a×1 + 1² ] - ( b² )²
= ( 2a - 1 )² - ( b² )²
= ( 2a - 1 + b² )( 2a - 1 - b² )
•••••
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