Math, asked by pallavi2k963, 6 months ago

factorise 4a^2+4a-3​

Answers

Answered by jironbasumatari
4

Answer:

solution: 4a²+4a -3

= 4a²+(6-2)a-3

= 4a²+6a-2a-3

= 2a(2a+3)-1(2a+3)

= (2a+3)(2a-1)

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