Question

Factorise : 4a^2-b^2+6b-9

Answer 1

hey mate here is your answer

by using identities

(a-b)²=a²-2ab+b²

and (a²-b²)=(a+b)(a-b)

4a²-b²+6b-9

4a²-(b²-6b+9)

(2a)²-(b²-(2)(3)(b)+3²)

(2a)²-(b-3)²

(2a-(b-3))(2a+(b-3))

(2a-b+3)(2a+b-3)

hope it will help you

mark me brainliest ✌✌✌✌⛄

Answer 2

= 4a² - b² + 6b - 9

= 4a ² - ( b² - 6b + 9)

using (a+b)² = a² - 2ab + b²

= 4a² - (b - 3)²

= 2²a² - (b - 3)²

= (2a)² - (b -3 )²

using (a+b)(a-b) = a² - b²

= [ 2a + ( b - 3 )] [ 2a - (b -3)]

= ( 2a + b - 3 ) ( 2a - b + 3 ) is ur answer!!!! plzzzz mark brainliest!!!! plzzzzzzz