Factorise : 4a^2-b^2+6b-9
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4a^ 2 - ( b^2 - 6b + 9 )
= (2a)^2 - (b - 3)^2
= (2a + b - 3)(2a - b + 3)
= (2a)^2 - (b - 3)^2
= (2a + b - 3)(2a - b + 3)
Answered by
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hey mate here is your answer
by using identities
(a-b)²=a²-2ab+b²
and (a²-b²)=(a+b)(a-b)
4a²-b²+6b-9
4a²-(b²-6b+9)
(2a)²-(b²-(2)(3)(b)+3²)
(2a)²-(b-3)²
(2a-(b-3))(2a+(b-3))
(2a-b+3)(2a+b-3)
hope it will help you
mark me brainliest ✌✌✌✌⛄
by using identities
(a-b)²=a²-2ab+b²
and (a²-b²)=(a+b)(a-b)
4a²-b²+6b-9
4a²-(b²-6b+9)
(2a)²-(b²-(2)(3)(b)+3²)
(2a)²-(b-3)²
(2a-(b-3))(2a+(b-3))
(2a-b+3)(2a+b-3)
hope it will help you
mark me brainliest ✌✌✌✌⛄
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