Question

Factorise
(4a-3b)^2+48ab

Answer 1

$your \: answer$
given :-

(4a-3b)2+48ab

now first opening the bracket

(4a-3b)2=16a2+3b2-24ab

so

16a2+9b2-24ab+48ab
= 16a2+9b2 +24 ab

this is forming an identity
=(4a+3b)2

answer =(4a+3b)2

Answer 2

$<b><font face=Copper black size=4 color=purple>$
Hello guys!

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= (4a)² - 2.4a.3b + (3b)² + 48ab

= 16a² - 24ab + 9b² + 48ab

= 16a² + 24ab + 9b²

= (4a)² + 2.4a.3b + (3b)²

= (4a + 3b)²

= (4a + 3b) (4a + 3b)

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