Question

Factorise : 4a2
+12ab +9b2
-8a-12b

Answer 1

4a²+12ab +9b²-8a-12b. =(2a+3b)²-4(2a+3b)

Answer 2

Answer:

The factorization of the given expression is (2a+3b)(2a+3b-4)

Step-by-step explanation:

We have to factorize the expression $4a^2+12ab+9b^2-8a-12b$

Let us group the expressions as

$(4a^2+12ab+9b^2)+(-8a-12b)$

Now, we can write the first group as a perfect square and take GCF from second group.

$((2a)^2+2\times2a\times3b+(3b)^2-4(2a+3b)\\=(2a+3b)^2-4(2a+3b)\\=(2a+3b)(2a+3b-4)$

Thus, the factorization of the given expression is (2a+3b)(2a+3b-4)