Question

factorise 4a²- 18a - 16 by splitting the middle term.please give me right answer.​

Answer 1

Answer:

STEP

1

:

Equation at the end of step 1

(22a2 - 18a) - 36

STEP

2

:

STEP

3

:

Pulling out like terms

3.1 Pull out like factors :

4a2 - 18a - 36 = 2 • (2a2 - 9a - 18)

Trying to factor by splitting the middle term

3.2 Factoring 2a2 - 9a - 18

The first term is, 2a2 its coefficient is 2 .

The middle term is, -9a its coefficient is -9 .

The last term, "the constant", is -18

Step-1 : Multiply the coefficient of the first term by the constant 2 • -18 = -36

Step-2 : Find two factors of -36 whose sum equals the coefficient of the middle term, which is -9 .

-36 + 1 = -35

-18 + 2 = -16

-12 + 3 = -9 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -12 and 3

2a2 - 12a + 3a - 18

Step-4 : Add up the first 2 terms, pulling out like factors :

2a • (a-6)

Add up the last 2 terms, pulling out common factors :

3 • (a-6)

Step-5 : Add up the four terms of step 4 :

(2a+3) • (a-6)

Which is the desired factorization

Final result :

2 • (a - 6) • (2a + 3)

Answer 2

Answer:

8 is the correct answer

thank you.....