Question

Factorise:4a²-9b²-2a-3b

Answer 1

$\textbf {Hey there, here is the solution.}$

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4a² - 9b² - 2a - 3b

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write the first two terms in perfect square:

= (2a)² - (3b)² - (2a + 3b)

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Apply (a² - b²) = (a + b)(a - b):

= (2a + 3b) (2a - 3b) - (2a + 3b)

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Take out common factor (2a + 3b):

= (2a + 3b) [ (2a - 3b) - 1 ]

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Evaluate the second bracket:

= (2a + 3b)( 2a - 3b - 1)

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Answer: (2a + 3b)( 2a - 3b - 1)

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⭐$\textbf {Cheers @ Simmisai }$⭐

Answer 2

Answer:

(2a+3b)(2a−3b−1)

Step-by-step explanation:

4a² - 9b² - 2a - 3b  

={(2a)²−(3b)²}−(2a+3b)  

={(2a+3b)(2a−3b)}−(2a+3b)  

=(2a+3b)(2a−3b−1)