Question

factorise 4c square+3c-10

Answer 1

Solution:

4c²+3c-10

The given expression is of the form
ax²+bx+c, where a=4 , b = 3 ,c = -10

In order to factorise a given expression we have to find two numbers p & q

p+ q = b , p+q = 3

pq= ac, pq= -40

We have to find two factors of - 40 such that their sum is - 3

8-5= 3 & 8×-5=-40


4c²+3c-10

4c² + 8c -5c -10

By middle term splitting

4c( c+2) - 5 (c +2)

(4c -5) (c+2)

4c²+3c-10= (4c -5) (c+2)

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Hope this will help you...

Answer 2

Let me help you with this question.
Given expression is,
4c² + 3c - 10
and we have to factorize it.
Comparing above expression with the general form of quadratic equation,
ax² + bx - c, we get:
a = 4
b = 3
c = -10
Now, factorization means that we have to choose two numbers whose product should be equal to
ac = (4) (-10) = - 40
and the sum of those two numbers should be equal to 
b = 3
Hence, 
4c² + 3c - 10 = 4c² + 8c - 5c - 10
                     = (4c² + 8c) - (5c + 10)
                     = 4c (c + 2) - 5 (c + 2)
                     = (4c - 5) (c + 2)
These are the required factors of the given expression.
Hope it helps you. Thanks.