Question

the mean of the set of numbers 6, 3, x, 4, 3, 5 and Y is given as y what is the value of x + Y

Answer 1

may be question is wrong please check the again

Answer 2

Answer:

The solution is $6y-x=21$

Step-by-step explanation:

Given : The mean of the set of numbers 6, 3, x, 4, 3, 5 and y  is given as y.

To find : What is the value of x+y?

Solution :

Mean is defined as the sum of all the numbers divided by number of terms.

$M=\frac{\sum x_i}{N}$

$y=\frac{6+3+x+4+3+5+y}{7}$

$y=\frac{21+x+y}{7}$

$7y=21+x+y$

$6y=21+x$

$6y-x=21$

Therefore, The solution is $6y-x=21$