Question

Factorise 4p^2+2q^2+p^2q^2+8

Answer 1

4p² + 2q² + p²q² + 8

8 + 4p² + 2q² + p²q²

4(2 + p²) + q²(2 + p²)

(4 + q²) (2 + p²)

Answer 2

Answer: (4 + q²) (2 + p²)

Step-by-step explanation:

Step1: 4p² +2q²  + p²q² + 8

Group by common factor

= 8 + 4p² + 2q² + p²q²

=  (p²q² + 4p²) + (2q² + 8)

= 4(2 + p²) + q²(2 + p²)

= (4 + q²) (2 + p²)

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