Question

factorise 4x^2-4px+(p^2-q^2)​

Answer 1

Answer:

a = 4

b = -4p

c = (p² - q²)

$x = \frac{ - b \pm \: \sqrt{ {b }^{2} - 4ac } }{2}$

$x = \frac{4p \: \pm \: \sqrt{ {16p}^{2} - 4 \times 4 \times ( {p}^{2} - {q}^{2}) } }{2 \times 4}$

$x = \frac{4p \pm \: \sqrt{ {16p}^{2} - {16p}^{2} } }{8}$

$x = \frac{4p \pm \: 4q}{8}$

$\frac{p + q}{2} \frac{p - q}{2}$