Math, asked by 2385purtijain, 1 month ago

factorise 4x^2+4x-15

Answers

Answered by SanaArmy07
4

Answer:

\large\mathtt\red{(2x+5)(2x-3)}

Hope it helps you!

Attachments:
Answered by JyotiJyoti8871
1

Answer:

How to solve your problem

4x²+4x-15

1) Use the sum-product pattern

4x²+4x-15

4x²+10x-6x-15

2) Common factor from the two pairs

4x²+10x-6x-15

2x(2x+5) - 3(2x+5)

3) Rewrite in factored from

2x(2x+5) - 3(2x+5)

(2x-3) (2x+5)

Solution

(2x-3) (2x+5)

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