Find the inner curved surface area and weight of a lead pipe 3.5 m long , if the external diameter of the pipe is 2.4 cm and the thickness of the lead is 2 mm and 1 cu cm of lead weights 11 g .
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Answer:
We know that,
d
2
2.4
2
R =
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= 1.2cm
External Radius (R) = 1.2cm
Thickness 2mm 0.2cm
Inner Radius (r)
= 1cm
Height (h) = 3.5cm 350cm Volume of hollow cylinders= (R² — r²)h
22
7
22
x (1.2² - 1²) × 350
7 x (1.44 - 1) x 350
= 22 x 0.44 x 50
44 100 = 22 x X 50
= 484cm³
Weight of 1cm³ = 11g
Weight of 484cm³ = 484 × 11
= 5324g
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