Math, asked by raunaksalu509, 9 months ago

factorise:4x^2-8x+3

Answers

Answered by RNR4Nikitha
8

Answer:

4x ^{2}  - 8x + 3 = 0 \\ 4x^{2}  - 2x - 6x + 3 = 0 \\ 2x(2x - 1) - 3(2x - 1) = 0 \\ (2x - 1)(2x - 3) = 0 \\ 2x - 1 = 0 \: (or) \: 2x - 3 = 0 \\ 2x = 1(or)2x = 3 \\ x =  \frac{1}{2} (or)x =  \frac{3}{2}

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Answered by yuvrajrajput8227
3

Answer:

This is your answer.❤❤

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