Math, asked by urvashi613, 11 months ago

Factorise : 4x^2-9y^3+20x+25

Answers

Answered by Anonymous
42

Step-by-step explanation:

4x^2 -9y^2+20x +25

= (2x)^2 +2×2x×5 +(5)^2 -9y^2

= (2x+5)^2 -(3y)^2

=(2x+5-3y)(2x+5+3y)

Answered by singhjack994
19

Answer:

(2x+5-3y)(2x+5+3y)

Step-by-step explanation:

4x^2+20x+25-9y^2

4x^2+20x+25

{(a+b)^2=a^2+2ab+b^2}

4x^2=(2x)^2=》a=2c

25=(5)^2=b=5

2ab=2×2x×5=20x

4x^2+20x+25=(2x+5)

4x^2 +20x+25-9y^2

(2x+5)^2-9^2

[using:a^2-b^2=(a-b)(a+b)]

witha= 2x +5&b=3y

(2x+5)^2-9y^2

answer is (2x+5-3y)(2x+5+3y)

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