factorise 4X square + 9 y square + 16 z square + 12 x y - 24 yz-16xz
Answers
Answered by
43
4x²+9y²+16z²+12xy-24yz-16xz
= (2x)²+(3y)²+(-4z)²+2[(2x)(3y)+(3y)(-4z)+(-4z)(2x)]
=(2x+3y-4z)²
Answered by
17
4x^2 + 9y^2 + 16z^2 + 12xy - 24yz - 16xz
= ( 2x)^2 + (3y)^2 + ( - 4z)^2 + 2(2x)(3y) + 2(3y)(-4z) + 2(-4z)(2x)
= ( 2x + 3y - 4z)^2
= ( 2x)^2 + (3y)^2 + ( - 4z)^2 + 2(2x)(3y) + 2(3y)(-4z) + 2(-4z)(2x)
= ( 2x + 3y - 4z)^2
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