Question

factorise 4x²-20xy+25y²​

Answer 1

4

x

2

−

20

x

y

+

25

y

2

=

4

x

2

−

10

x

y

−

10

x

y

+

25

y

2

=

2

x

(

2

x

−

5

y

)

−

5

y

(

2

x

−

5

y

)

=

(

2

x

−

5

y

)

(

2

x

−

5

y

)

Answer 2

Answer:

(2x-5y) ^ 2

Step-by-step explanation:

4x^2 - 10xy - 10xy + 25y^2

= 2x ( 2x - 5y ) - 5y (2x - 5y)

= (2x - 5y) ( 2x-5y)

= (2x-5y) ^ 2

*method 2*

4x²-20xy+25y²

= (2x)^2 + (5y)^2 - 2(2x)(5y)

[ note: here the identity __(a-b)^2 = a^2 + b^2 - 2ab __ is used ]

= (2x-5y) ^ 2

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