Question

Factorise 4x²-9x-96​

Answer 1

Step-by-step explanation:

Factoring  4x2-9x-96 

The first term is,  4x2  its coefficient is  4 .

The middle term is,  -9x  its coefficient is  -9 .

The last term, "the constant", is  -96 

Step-1 : Multiply the coefficient of the first term by the constant   4 • -96 = -384 

Step-2 : Find two factors of  -384  whose sum equals the coefficient of the middle term, which is   -9 .

     -384   +   1   =   -383  

   -192   +   2   =   -190 

    -128   +   3   =   -125   

  -96   +   4   =   -92  

   -64   +   6   =   -58 

    -48   +   8   =   -40   

  -32   +   12   =   -20   

  -24   +   16   =   -8   

  -16   +   24   =   8   

  -12   +   32   =   20  

   -8   +   48   =   40  

   -6   +   64   =   58  .

   -4   +   96   =   92  

   -3   +   128   =   125   

  -2   +   192   =   190   

  -1   +   384   =   383

Observation : No two such factors can be found !! 

Conclusion : Trinomial can not be factored

try to solve this question by using quadratic formula...which is root of b^2 -4ac whole divide by 2a