Question

factorise 4x²+9y²+12xy+4xz+6yz​

Answer 1

Answer:

We know that

(x

2

+y

2

+z

2

+2xy+2yz+zx)=(x+y+z)

2 4x 2+9y 2 +16z 2

+12xy−24yz−16xz

=(2x)

2

+(3y)

2

+(−4z)

2

+2(2x)(3y)+2(3y)(−4z)+2(−4z)(2x)

=(2x+3y−4z)

2

=(2x+3y−4z)(2x+3y−4z)