Question

Factorise: 4x2 + 9y2 + 16z2 + 12xy – 24yz –16xz.

Answer 1

$Given \: 4x^{2} + 9y^{2}+16z^{2}+12xy-24yz-16xz$

$= (2x)^{2}+(3y)^{2}+(-4z)^{2}+2\times(2x)(3y)+2\times(3y)(-4z) + 2\times(-4z)(2x)$

/* By algebraic identity */

$\boxed{ \blue{ (a+b+c)^{2}=a^{2}+b^{2}+c^{2}+2ab+2bc+2ca}}$

$= ( 2x + 3y - 4z )^{2}$

$= ( 2x + 3y - 4z )( 2x + 3y - 4z )$

Therefore.,

$\red{ 4x^{2} + 9y^{2}+16z^{2}+12xy-24yz-16xz }$

$\green {= ( 2x + 3y - 4z )( 2x + 3y - 4z )}$

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Answer 2

Answer:

(2x+3y+8y)(2x+3y+8y)

Step-by-step explanation:

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