Factorise 4x²+9y²-25z²+12xy
GeniusYH:
(2x + 3y - 5z)(2x + 3y + 5z)
Answers
Answered by
27
HI,
============
Fist step:-→ 4x² + 9y² - 25z² + 12xy
2nd step→(2x)² + (3y)² - (5z)² + 2(2x)(3y)
3rd step:-→(2x)² + 2(2x)(3y) + (3y)² - (5z)²
4th step:-→(2x + 3y)² - (5z)²
Final answer:-∴(2x + 3y + 5z)(2x + 3y - 5z) ======================================
Now,
We can't factor it further...
=================
:-)
============
Fist step:-→ 4x² + 9y² - 25z² + 12xy
2nd step→(2x)² + (3y)² - (5z)² + 2(2x)(3y)
3rd step:-→(2x)² + 2(2x)(3y) + (3y)² - (5z)²
4th step:-→(2x + 3y)² - (5z)²
Final answer:-∴(2x + 3y + 5z)(2x + 3y - 5z) ======================================
Now,
We can't factor it further...
=================
:-)
Answered by
13
Solution:
_____________________________________________________________
Given & To Find:
Factorize:
4x²+9y²-25z²+12xy
_____________________________________________________________
we know the two identites (By using these we are going to solve this problem),
(a + b)² = a² + 2ab + b²,
a² - b² = (a + b)(a - b),.
Going back to the expression,
=> 4x² + 9y² - 25z² + 12xy
=> (2x)² + (3y)² - (5z)² + 2(2x)(3y)
=> (2x)² + 2(2x)(3y) + (3y)² - (5z)²
=>(2x + 3y)² - (5z)² (By using (a + b)² identity)
=> (2x + 3y + 5z)(2x + 3y - 5z),. (By using a² - b² identity),.
_____________________________________________________________
Hope it Helps !!
_____________________________________________________________
Given & To Find:
Factorize:
4x²+9y²-25z²+12xy
_____________________________________________________________
we know the two identites (By using these we are going to solve this problem),
(a + b)² = a² + 2ab + b²,
a² - b² = (a + b)(a - b),.
Going back to the expression,
=> 4x² + 9y² - 25z² + 12xy
=> (2x)² + (3y)² - (5z)² + 2(2x)(3y)
=> (2x)² + 2(2x)(3y) + (3y)² - (5z)²
=>(2x + 3y)² - (5z)² (By using (a + b)² identity)
=> (2x + 3y + 5z)(2x + 3y - 5z),. (By using a² - b² identity),.
_____________________________________________________________
Hope it Helps !!
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