factorise 4x³+8x²+x-3
Answers
Answered by
4
this is easy way hope you
Attachments:
Rimjhim58:
thank you but I didn't understand
send ur number or id i will send pic
no, thanks.
Answered by
15
Given,
p(x) = 4x³+8x²+x-3
putting (x+1)= 0 or x= -1 in p(x)
We get,
p(-1) = 4(-1)³+ 8(-1)²+(-1)-3
= -4 + 8 -1 -3
= 0
So,
(x+1) is a factor of p(x),
Divide the p(x) by (x+1)
We get quoteint,
= 4x² + 4x -3
= 4x² -2x + 6x -3
= 2x(2x-1) + 3(2x -1)
= (2x+3)(2x-1)
Therefore,
4x³+8x²+x-3= (2x+3)(2x-1)(x+1)
Refer to attachment.
p(x) = 4x³+8x²+x-3
putting (x+1)= 0 or x= -1 in p(x)
We get,
p(-1) = 4(-1)³+ 8(-1)²+(-1)-3
= -4 + 8 -1 -3
= 0
So,
(x+1) is a factor of p(x),
Divide the p(x) by (x+1)
We get quoteint,
= 4x² + 4x -3
= 4x² -2x + 6x -3
= 2x(2x-1) + 3(2x -1)
= (2x+3)(2x-1)
Therefore,
4x³+8x²+x-3= (2x+3)(2x-1)(x+1)
Refer to attachment.
Attachments:
Great answer .
Similar questions