Math, asked by bhavana02092006, 1 month ago

factorise
4y^2+28y-120

Answers

Answered by bibhaasrana
0

Answer:

4(y^2+7y-30)

I think this will help

Answered by gayathriandsruthifun
1

Answer:

 {4y}^{2}  + 28y - 120 \\  - 120 \times 4 = -  480\\  - 480 = 40 \times  - 12 \\ 40 - 12 = 28 \\  =  {4y}^{2}  + 40y - 12y - 120 \\ =  4y(y + 10) - 12(y + 10) \\  = (y + 10)(4y - 12)

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