Question

factorise 4y^2 - 4y + 1​

Answer 1

Answer:

$(2y^{2} ) ^{2} - 2 \times 2y \times 1 + 1 ^{2}$

$(2y) ^{2} - 2 \times 2y \times 1 + 1 ^{2}$

Using the identity:

$a ^{2} - 2ab + b ^{2} =( a - b) ^{2}$

Step-by-step explanation:

A= 2y, B=1

$(2y - 1) ^{2}$

Explaination:

We will write 4y^2 in the form of; (2y^2)^2

Expand 4y as; -2×2y×1