Question

The velocity-time graph of a ball of mass 200 g moving along the straight line under the action of 10 N

force is given below. Find the friction force exerted by the floor on the ball.​

Answer 1

Explanation:

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Answer 2

Given:

The velocity-time graph of a ball of mass, $m=200g$ moving in a straight line under the action of a force, $F=10N$.

To Find:

Force of friction exerted by the floor, $f=?$

Solution:

We know that the acceleration of a particle is given by the slope of its velocity-time graph

So,     $a=\frac{v-v_o}{t-t_o}$

     ⇒ $a=\frac{20-10}{2-0}$

     ⇒ $a=5m/s^2$

The total force being applied to the body can be found by $F=ma$,

                                                                                                $=0.2*5$

                                                                                                $=1N$

   The net force on the body $=1N$

⇒ $F_{NET}=1N$

⇒ $F-f=1N$

⇒ $f=9N$

Hence, the frictional force acting on the body by the floor is equal to 9N.