Question

Factorise 4y² - 12y + 9.

Give proper answer!!!​

Answer 1

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Observe,

$\sf{4y^2 = (2y)^2, 9 = 3^2}$ and $\sf{12y = 2 × 3 × (2y)}$

Therefore,

$\sf{4y^2 - 12y + 9}$

$\sf{= (2y)^2 - 2 × 3 × (2y) + (3)^2}$

$\sf{= (2y - 3)^2}$

⠀⠀⠀⠀⠀⠀⠀$\boxed{\sf{\green{(Required\: factorisation)}}}$

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${\huge{\underline{\small{\mathbb{\blue{HOPE\:HELPS\:UH :)}}}}}}$

$\red{\tt{sωєєтcнαям♡~}}$

Answer 2

Step-by-step explanation:

3m2 + 9m + 6 3m2 + 3m + 6m + 6 3m ( m + 1 ) +6 ( m + 1 ) ( m + 1 ) ( 3m + 6 ) 3 ( m + 1 ) ( m + 2 ) Hope this helps

Factorize it by the middle term technique/Splitting middle term technique.

4y? - 6у — 6у +9

2y (2у — 3) — 3(2у 3)

(2у — 3) (2у — 3) -> (2у — 3)?

Method 2:- -4y+9-12y I used (a-b)2-a?+b?-2ab