Question

Factorise 4y² + 49t² - 28ty

Answer 1

QUESTION: Factorise 4y² + 49t² - 28ty

SOLUTION: by using the identity (a-b)² = a² -2ab +b² we get:

=> 4y² + 49t² - 28ty

=> (2y)² +(7t)² -2(2y)(7t)

=> (2y + 7t)²

Hence, (2y + 7t)² is your answer

Answer 2

Answer:

$4 {y}^{2} + 49 {t}^{2} - 28ty$

Step-by-step explanation:

by using the formula

$(a - b) ^{2} = {a}^{2} - 2ab + {b}^{2}$

so,

$( {2y})^{2} +(7t)^{2} - 2(4 \times 7)ty$

so the answer is

$(2y - 7t)^{2}$