Question

Factorise (4y² + 4y – 24) ÷ (2y + 6)

Answer 1

Answer:

2×(y-3)(y+2)/(y+3)

Step-by-step explanation:

(4y^2-4y-24)/(2y+6)

={4(y^2-y-6)}/{2(y+3)}

=4×(y^2-3y+2y-6)/{2×(y+3)}

=4×(y-3)×(y-2)/{2(y+3)}

=2×(y-3)(y+2)/(y+3)