Question

factorise 5 - 14x - 3x^2​

Answer 1

Answer:

3x^2 + 14x - 5

x^2 + 14x - 15

(x+15/3)(x-1/3)

(x+5)(x+1/3)

= (x+5)(3x-1)

Step-by-step explanation:

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Answer 2

STEP

1

:

Equation at the end of step 1

(5 - 14x) - 3x2

STEP

2

:

STEP

3

:

Pulling out like terms

3.1 Pull out like factors :

-3x2 - 14x + 5 = -1 • (3x2 + 14x - 5)

Trying to factor by splitting the middle term

3.2 Factoring 3x2 + 14x - 5

The first term is, 3x2 its coefficient is 3 .

The middle term is, +14x its coefficient is 14 .

The last term, "the constant", is -5

Step-1 : Multiply the coefficient of the first term by the constant 3 • -5 = -15

Step-2 : Find two factors of -15 whose sum equals the coefficient of the middle term, which is 14 .

-15 + 1 = -14

-5 + 3 = -2

-3 + 5 = 2

-1 + 15 = 14 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -1 and 15

3x2 - 1x + 15x - 5

Step-4 : Add up the first 2 terms, pulling out like factors :

x • (3x-1)

Add up the last 2 terms, pulling out common factors :

5 • (3x-1)

Step-5 : Add up the four terms of step 4 :

(x+5) • (3x-1)

Which is the desired factorization

Final result :

(1 - 3x) • (x + 5)