Math, asked by faidankhan144, 10 months ago

factorise 5(3a+b)²+6(3a+b)-8​

Answers

Answered by Anonymous
57

3a+b+2)*(15a+5b-4)

Step-by-step explanation:

5(3a+b)*(3a+b)+6(3a+b)-8

Rewrite

5(3a+b)^2+10(3a+b)-4(3a+b)-8

Factor the expressions

5(3a+b)*(3a+b+2)-4(3a+b=2)

Factor the expressions

(3a+b+2)*(5(3a+b)-4)

Multiply paranthesis by 5

(3a+b+2)*(15a+5b-4)

Answered by FelisFelis
99

(3a+b+2)(15a+5b-4)

Step-by-step explanation:

Consider the provided expression.

5(3a+b)²+6(3a+b)-8​

Let us consider that (3a+b)=x

5x²+6x-8

Now factories as shown

5x²+10x-4x-8

5x(x+2)-4(x+2)

(x+2)(5x-4)

Now substitute the value of x in above expression.

(3a+b+2)(5(3a+b)-4)

(3a+b+2)(15a+5b-4)

Hence, the factorization of the expression is (3a+b+2)(15a+5b-4).

#Learn more

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