factorise 5-4(x-y)-12(x-y)^2
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5 - 4 (x - y) - 12 (x - y)²
= (1 - 2x + 2y) (5 + 6x - 6y)
Explanation:
Now, 5 - 4 (x - y) - 12 (x - y)²
= 5 - (10 - 6) (x - y) - 12 (x - y)²
= 5 - 10 (x - y) + 6 (x - y) - 12 (x - y)²
= 5 {1 - 2 (x - y)} + 6 (x - y) {1 - 2 (x - y)}
= {1 - 2 (x - y)} {5 + 6 (x - y)}
= (1 - 2x + 2y) (5 + 6x - 6y)
This is the required factorization.
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