Question

Factorise 5(x+y)^2+33(xy)-14

Answer 1

Hey dear here is your answer

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I think there is a mistake in your question. it's impossible. if the question is 5(xy)^2+33(xy)-14 then the answer is
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(sorry for the handwriting)

hope it help!!

Answer 2

$Well ,\: \: I \: \: think \: \: that \: \: the \\ term \: \: is \: \: {(xy)}^{2} . \\ \\ Now ,\: \: 5 {(xy)}^{2} + 33xy - 14 \\ \\ = 5 {x}^{2} {y}^{2} + (35 - 2)xy - 14 \\ \\ = 5 {x}^{2} {y}^{2} + 35xy - 2xy - 14 \\ \\ = 5xy(xy + 7) - 2(xy + 7) \\ \\ = (xy + 7)(5xy - 2) ,\\ \\ which \: \: is \: \: th e\: \: required \: \: answer .\\ \\ Thank \: \: you \: \: for \: \: the \: \: question.$