factorise 512x^9+1
hopes someone help me
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Yess, I can help you.
given
512x^9 + 1
=(8x³)³+(1)³
=(8x³+1){(8x³)²-8x²+1²}
=(8x³+1)(64x^6-8x³+1)
={(2x)³+(1)³}(64x^6-8x³+1)
=(2x+1)(4x²-2x+1)(64x^6-8x³+1)
given
512x^9 + 1
=(8x³)³+(1)³
=(8x³+1){(8x³)²-8x²+1²}
=(8x³+1)(64x^6-8x³+1)
={(2x)³+(1)³}(64x^6-8x³+1)
=(2x+1)(4x²-2x+1)(64x^6-8x³+1)
Anonymous:
thanks
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