Math, asked by SIRGERARD10, 1 year ago

Factorise 54x^2 + 42x^3 - 30x^4.

Answers

Answered by shailendrachoubay216
2

Answer:

The answer is -6x^2(5x^2 - 7x -9) which can be factorised further to give -30x^2(x - 2.213)(x + 0.813)

Step-by-step explanation:

It is given to factorise 54x^2 + 42x^3 - 30x^4.

To factorise we first take any common terms of the expression given.

So the expression becomes

54x^2 + 42x^3 - 30x^4 = x^2( 54 + 42x - 30 x^2) = -6x^2(5x^2 - 7x -9)

So we see the term left in brackets after taking out the common terms is quadratic in nature.

The quadratic equation cannot be factorised  further into terms with whole numbers as the roots of the quadratic equation are radical in nature. But we can continue to factorise.

Roots of the quadratic equation are x = \frac{7 + \sqrt{49 + 180} }{10}  = 2.213

and \frac{7 - \sqrt{49 + 180} }{10}  = -0.813

Therefore the complete factorisation is given by -30x^2(x - 2.213)(x + 0.813)

Answered by niharikashekhawat311
0

6x^2(−5x^2+7x+9) is the correct answer

Similar questions