factorise 5a^+13a+6 by splitting the middle term
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Answered by
14
solution.
= 5a^2+10a+3a+6
= 5a ( a+2)+ 3 (a+ 2)
= (5a+ 3) ( a+ 2)
Now, 5a+ 3=0 or, a+2=0
=> a= -3/5 or a= -2
________
hope it helps☺✌✌
= 5a^2+10a+3a+6
= 5a ( a+2)+ 3 (a+ 2)
= (5a+ 3) ( a+ 2)
Now, 5a+ 3=0 or, a+2=0
=> a= -3/5 or a= -2
________
hope it helps☺✌✌
Answered by
17
5a²+13a+6
-> 5a²+10a+3a+6
-> 5a(a+2)+3(a+2)
(5a+3)(a+2)
IF U ONLY WANT TO FACTORISE, THE ANSWER IS (5a+3)(a+2).
IF U WANT FURTHER SOLUTION, SET IT EQUAL TO 0 AND GET THE FOLLOWING ANSWER.
a=-2 or
a=-3/5
-> 5a²+10a+3a+6
-> 5a(a+2)+3(a+2)
(5a+3)(a+2)
IF U ONLY WANT TO FACTORISE, THE ANSWER IS (5a+3)(a+2).
IF U WANT FURTHER SOLUTION, SET IT EQUAL TO 0 AND GET THE FOLLOWING ANSWER.
a=-2 or
a=-3/5
anupamnath1413:
Factorize 3 (2x-y)^ +14 (2x-y) +8 by splitting the middle term
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