Question

if one zero of the polynomial (m²+3)x²+23x+8 is reciprocal of the other, find the value of the m

Answer 1

value of m is √ 5 or -√5

Answer 2

Answer:

Value of m should be ±√5.

Step-by-step explanation:

If a polynomial is in the form of ax² + bx + c and there are two zeros are reciprocal to each other then

$p\times \frac{1}{p}=\frac{\text{constant term}}{\text{coefficient of }x^{2} } =\frac{c}{a}$

Now we apply this formula in the given polynomial

(m² + 3)x²+ 23x + 8

Then $p\times \frac{1}{p}=\frac{8}{(m^{2}+3)}$

$\frac{8}{(m^{2}+3)}=1$

$m^{2}+3=8$

$m^{2}=5$

m = ±$\sqrt{5}$

Therefore, the value of m should be ±$\sqrt{5}$.

Learn more about the reciprocal zeros from https://brainly.in/question/3367764