Question

Factorise :(5r + 2)2
-(2r − 1)2
fast plz​
I'll mark brainliest confirm
please

Answer 1

Answer:

=(5r+2+2r-1) {5r+2-(2r-1)}

= (7r+1)(5r+2-2r+1)

= (7r+1)(3r+3)

Answer 2

Answer: $10r^{2} +4+20r-(4r^{2} +1-4r) = 10r^{2} +4+20r-4r^{2} -1+4r$

=> $6r^{2} +24r+3$=0

=> $3(2r^{2} +8r+1)$=0

$(2r^{2} +8r+1)$=0

r=$\frac{-8 ±\sqrt{64-4*2*1} }{4}$

r=$\frac{-8+\sqrt{56} }{4}$ or $\frac{-8-\sqrt{56} }{4}$

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