Question

factorise 5y²+5y-10​

Answer 1

5y²+5y-10​

= 5 (y² + y - 2)​

= 5 (y² + 2y - y - 2)​

= 5 { y(y+2) - 1(y+2) }

= 5 { (y+2) (y-1)

= 5 (y+2) (y-1)

Answer 2

ANSWER:

→ 5y² + 5y - 10

Taking common

→ 5(y² + y - 2)

Factorising by splitting the middle term

→ 5[y² + 2y - y - 2]

Taking common

→ 5[ y(y + 2) - 1(y + 2) ]

→ 5[ (y - 1)(y + 2) ]

Hence, factorised

MORE INFO:

→ (a + b)² = a² + b² + 2ab

→ (a - b)² = a² + b² - 2ab

→ a² - b² = (a + b)(a - b)

→ a² + b² = (a + b)² - 2ab

Quadratic equation formula

→ x = -b ± √b² - 4ac/2a