Question

Factorise 5z^2-80 using identity​

Answer 1

Answer:

$\large\boxed{\sf{5(z+4)(z-4)}}$

Step-by-step explanation:

We have to factorise,

$5 {z}^{2} - 80$

Taking, 5 as common, we will get,

$= 5( {z}^{2} - 16)$

But, we know that,

• $16 = {4}^{2}$

Further simplifying, we will get,

$= 5( {z}^{2} - {4}^{2} )$

But, we know that,

${x}^{2} - {y}^{2} = (x + y)(x - y)$

Therefore, we will get,

$= 5(z + 4)(z - 4)$

Hence, the required answer is 5(z+4)(z-4)

Answer 2

Step-by-step explanation:

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